Monday, September 9, 2013

SP#1: Unit E Concept 1: Identifying x-intercepts, vertex, axis of quadratics and graphing them. Quadratrics in standard form

1. First step to solve is to add a 12 so the equation becomes -6x^2+24x=12
2. Then factor out a -6 while putting a -6 on the other side. -6(x^2-4x___)=12 -6(__)
3. divide the -4 by 2 then square it which becomes -4/2=-2^2=4
4. Plug the four into both sides and then simplify.
-6(x^2-4x+4)=12-6(4)
5. The equation then becomes -6(x-2)^2=-12
6. Divide -6 so the equation becomes (x-2)^2=2
7. Square root both sides which becomes x-2= square root of 2
8. Once the square root has been distributed the answer becomes + or - square root of 2.
9. Add 2 to the other side.
10. The equation is now x= 2+ square root of 2
and x= 2- square root of 2. These are the x intercepts.

To find the parent equation you take the equation -6(x-2)^2=-12 and add 12
To find the vertex you use the form (h,k) which is 2,12
To find the y intercept you plug in 0 for all x values of the standard equation.
To find the axis, the value is h of h,k which is 2


  The problem is about finding the parent graph equation. Also other things that must be found are the vertex, and whether it is max or min. The y-intercept must be found along with the axis and the x intercepts.

The viewer needs to pay close attention to the steps of whats being factored and the steps taken afterwards. Important things to take note is the b/2^2 part. Another thing to pay close attention is when you simplify you can simply take b/2 and use that as the equation.

No comments:

Post a Comment